[2024/05/03] Infinite exponential

2 years ago by siriusmart to c/dailymaths

Find x for x^x^x^x^x^... = 2

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SuperSpruce 15 points 2 years ago

First off, why did this post get downvoted?

Answer alert

The answer is sqrt(2), because sqrt(2)^2^ = 2, and you build the infinite exponential sequence by taking x_n = x^x_(n-1)^.

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siriusmart 11 points 2 years ago

yup there u go, btw can u please spoiler it so its harder for people to accidentally see it

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