- Show that it's possible
a^b=cwhereaandbare irrational, andcis rational.
Sry for the gap I ran out of ideas.
siriusmart 5 points 2 years ago
that is simply genius
(i suppose it didnt come to me when i think of "irrational")
siriusmart 4 points 2 years ago
this one got some table slams from my friends
Hint:
spoiler
Find an example which satisfies the equation.
Solution:
spoiler
zkfcfbzr 1 point 2 years ago
solution
e^(i*π) = -1
Also, anything like a^(log(c) / log(a)), for positive rational c and irrational a, to generalize bean_jamming's answer
I also assert without proof that in the equation x^x = c, x is irrational for most rational values of c
I did start trying out stuff with sqrt(2), thinking back to the tower power problems, but didn't end up coming up with your solution while doing so ¯\_(ツ)_/¯
dailymaths
@lemmy.world
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dailymaths
@lemmy.world
264
40
1
Share your cool maths problems.
Complete a challenge:
- Post your solution in comments, if it is exactly the same as OP's solution, let us know.
- Have fun.
Post a challenge:
- Doesn't have to be original, as long as it is not a duplicate.
- Challenges not riddles, if the post is longer than 3 paragraphs, reconsider yourself.
- Optionally include solution in comments, let it be clear this is not a homework help forums.
- Tag [unsolved] if you don't have a solution yet.
- Please include images, if your question includes complex symbols, attach a render of the maths.
Feel free to contribute to a series by DMing the OP, or start your own challenge series.
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e^(log 2) = 2 is rational
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