- Show that it's possible
a^b=cwhereaandbare irrational, andcis rational.
Sry for the gap I ran out of ideas.
a^b=c where a and b are irrational, and c is rational.Sry for the gap I ran out of ideas.
that is simply genius
(i suppose it didnt come to me when i think of "irrational")
@lemmy.world
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@lemmy.world
Share your cool maths problems.
Complete a challenge:
Post a challenge:
Feel free to contribute to a series by DMing the OP, or start your own challenge series.
go to feed...
e^(log 2) = 2 is rational
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