[2024/05/13] Irrational powers

2 years ago by siriusmart to c/dailymaths

  • Show that it's possible a^b=c where a and b are irrational, and c is rational.

Sry for the gap I ran out of ideas.

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been_jamming 6 points 2 years ago

e^(log 2) = 2 is rational

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siriusmart 5 points 2 years ago

that is simply genius

(i suppose it didnt come to me when i think of "irrational")

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