Let a and b be rational numbers and suppose that (a-b)=4 and a*b=1 . Show that (a+b)^2 = 20.

glowing_hans 4 points a year ago
hint

Use algebraic substitution and the binomial formulas

(a+b)^2 = a^2+2*ab+b^2
(a-b)^2 = a^2-2*ab+b^2
Solution
(a+b)^2 = a^2 + 2*ab + b^2 = (a-b)^2 +4*ab = 4^2+4*1 = 16+4 = 20 ◽
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siriusmart 1 point a year ago

of course the website has something to do with lean

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glowing_hans 2 points a year ago

yeah I found this website quite interesting even if I dont want to learn lean right now you can learn some cool proofs. Do you mind if I post other questions from that one here?

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