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zenharbinger

@lemmy.world

zenharbinger 271 points 2 years ago

48% of these kids frighten me.

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zenharbinger 101 points 3 years ago

The article says she let another person use her card for a fee.

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zenharbinger 55 points 2 years ago

Small Govt. say what?

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zenharbinger 33 points 3 years ago

some partitions are useful. Keeping /var and /tmp separate can stop DoS attacks by now allowing logs to fill the entire drive /home means you can wipe the / partition and keep user data.

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zenharbinger 32 points 3 years ago

This is the first thing I thought of as well. It's never been "just use what you want". It got better for a while as JavaScript and CSS normalized. Now it's trash again.

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zenharbinger 32 points 3 years ago

He has no cash, it's all tied up in real estate. He would have to sell to get the bond money.

Probably could get a 'donor' to purchase though.

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zenharbinger 29 points 2 years ago

Raphael, Raphael doesn't like people using preferred names, or pronouns.

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zenharbinger 27 points 2 years ago

That happens when you are a good developer too.

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zenharbinger 25 points 2 years ago

Vote

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zenharbinger 24 points 3 years ago

Shocked Picachu

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zenharbinger 21 points 2 years ago

They can use up to 2 years (I think) of a previous term. LBJ could have had 2 full terms plus the remainder he had from JFK.

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zenharbinger 19 points 2 years ago

I didn't think there was a floor.

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zenharbinger 19 points 3 years ago

buffer overflow in reality

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zenharbinger 18 points 3 years ago

I found the easiest way to think about it as if there are 10 doors, you choose 1, then 8 other doors are opened. Do you stay with your first choice, or the other remaining door? Or scale up to 100. Then you really see the advantage of swapping doors. You have a higher probability when choosing the last remaining door than of having correctly choosen the correct door the first time.

Edit: More generically, it's set theory, where the initial set of doors is 1 and (n-1). In the end you are shown n-2 doors out of the second set, but the probability of having selected the correct door initially is 1/n. You can think of it as switching your choice to all of the initial (n-1) doors for a probability of (n-1)/n.

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zenharbinger 18 points 3 years ago

22 obviously

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zenharbinger 17 points 2 years ago

color me not surprised, more shocked if they had no history

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zenharbinger 16 points 3 years ago

than

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zenharbinger 15 points 2 years ago

So much for Democracy Dies in Darkness

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zenharbinger 15 points 2 years ago

no. ok, done. you can deposit the funds otherwise used into my account.

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zenharbinger 15 points 2 years ago

file under LOL

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thanks for using Leebra!

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